Problem 30P

The position of a particle as a function of time is given by x = (-2.00 m/s)t + (3.00 m/s3)t3. (a) Plot x versus t for time from t = 0 to t = 1.00 s. (b) Find the average velocity of the particle from t = 0.150 s to t = 0.250 s. (c) Find the average velocity from t = 0.190 s to t = 0.210 s. (d) Do you expect the instantaneous velocity at t = 0.200 s to be closer to -1.62 m/s, or -1.66 m/s? Explain.

Solution 30P

Step 1 of 5:

First plot position vs time graph for the given particle.

Then calculate the average velocity of the particle for the given two ranges.

Then calculate which one from the given values will be more close to the instantaneous velocity of the particle at the 0.200 s.