Answer: An object moves uniformly around a circular path

Step 1 of 3

(a) We are asked to find the translational speed of the object:

Radius of the path, \(r=20 \mathrm{~cm}=0.2 \mathrm{~m}\)

Time period for complete revolution, T = 2s

Translational distance travelled by the object=circumference of the circular path = \(2 \pi r\)

Translational distance = \(2 \pi(0.2)=0.4 \pi \mathrm{m}\)

Translational speed = \(v=\frac{\text { distance }}{\text { time taken }}=\frac{2 \pi r}{T}\)

Translational speed is calculated as:

\(v=\frac{0.4 \pi}{2}=0.2 \pi \mathrm{m} / \mathrm{s}=0.628 \mathrm{~m} / \mathrm{s}\)

Thus, translational speed of the object is \(v=0.2 \pi \mathrm{m} / \mathrm{s}\) or 0.628m/s