Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr)

Chapter 12, Problem 3

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QUESTION:

Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr) eik(ct+r)]dk=1 4cr[(ct r)(ct +r)].

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QUESTION:

Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr) eik(ct+r)]dk=1 4cr[(ct r)(ct +r)].

ANSWER:

Step 1 of 5

To prove:- .

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