Solution Found!
Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr)
Chapter 12, Problem 3(choose chapter or problem)
QUESTION:
Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr) eik(ct+r)]dk=1 4cr[(ct r)(ct +r)].
Questions & Answers
QUESTION:
Show that 1 22cr 0sinkctsinkr dk =1 82cr [eik(ctr) eik(ct+r)]dk=1 4cr[(ct r)(ct +r)].
ANSWER:Step 1 of 5
To prove:- .