If eight defective and 12 nondefective items are inspected

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QUESTION:

If eight defective and 12 nondefective items are inspected one by one, at random and without replacement, what is the probability that (a) the first four items inspected are defective; (b) from the first three items at least two are defective?

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QUESTION:

If eight defective and 12 nondefective items are inspected one by one, at random and without replacement, what is the probability that (a) the first four items inspected are defective; (b) from the first three items at least two are defective?

ANSWER:

Step 1 of 2

Eight defective and 12 nondefective items are inspected one by one, at random and without replacement.

Let be the event that the  item is defective.

Since, items are inspected on by one without replacement, therefore,

Since, all events are mutually independent, by the law of multiplication,

Therefore, the probability that the first four items inspected are defective is .

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