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A ball thrown straight upward returns to its original

Chapter 4, Problem 72GP

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QUESTION:

Problem 72GP

A ball thrown straight upward returns to its original level in 2.75 s. A second ball is thrown at an angle of 40.0° above the horizontal. What is the initial speed of the second ball if it also returns to its original level in 2.75 s?

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QUESTION:

Problem 72GP

A ball thrown straight upward returns to its original level in 2.75 s. A second ball is thrown at an angle of 40.0° above the horizontal. What is the initial speed of the second ball if it also returns to its original level in 2.75 s?

ANSWER:

Step 1 of 2

Consider a ball is thrown vertically upward and return back in 2.75 s. Another ball is thrown at an angle ? above the horizontal and hits the ground. The time taken by the second ball is same as that of the first ball. We are going to find the initial speed of the second ball.

The initial speed of the second ball = vo

The time taken to hit the ground t = 2.75 s = tf

The angle above the horizontal ? = 40°

The acceleration due to gravity g = 9.81 m/s2

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