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IP To decide who pays for lunch, a passenger on a moving
Chapter 4, Problem 73GP(choose chapter or problem)
IP To decide who pays for lunch, a passenger on a moving train tosses a coin straight upward with an initial speed of and catches it again when it returns to its initial level. From the point of view of the passenger, then, the coin's initial velocity is \(\mathrm {(4.38\ m/s)\hat{y}}\). The train's velocity relative to the ground is \(\mathrm {(12.1\ m/s)\hat{x}}\). (a) What is the minimum speed of the coin relative to the ground during its flight? At what point in the coin's flight does this minimum speed occur? Explain. (b) Find the initial speed and direction of the coin as seen by an observer on the ground. (c) Use the expression for \(y_\mathrm{max}\) derived in Example
to calculate the maximum height of the
, as seen by an observer on the ground. (d) Calculate the maximum height of the coin from the point of view of the passenger, who sees only one-dimensional motion.
Equation Transcription:
Text Transcription:
(4.38 m/s)hat{y}
(12.1 m/s)hat{x}
y_{max}
Questions & Answers
QUESTION:
IP To decide who pays for lunch, a passenger on a moving train tosses a coin straight upward with an initial speed of and catches it again when it returns to its initial level. From the point of view of the passenger, then, the coin's initial velocity is \(\mathrm {(4.38\ m/s)\hat{y}}\). The train's velocity relative to the ground is \(\mathrm {(12.1\ m/s)\hat{x}}\). (a) What is the minimum speed of the coin relative to the ground during its flight? At what point in the coin's flight does this minimum speed occur? Explain. (b) Find the initial speed and direction of the coin as seen by an observer on the ground. (c) Use the expression for \(y_\mathrm{max}\) derived in Example
to calculate the maximum height of the
, as seen by an observer on the ground. (d) Calculate the maximum height of the coin from the point of view of the passenger, who sees only one-dimensional motion.
Equation Transcription:
Text Transcription:
(4.38 m/s)hat{y}
(12.1 m/s)hat{x}
y_{max}
ANSWER:
Step 1 of 7
Part (a)
A passenger inside a moving train tosses a coin upwards with an initial speed and catches the coin at the same level. The train moves at a constant speed in the x-direction. The motion of the coin is along the y-direction. We are going to find the minimum speed of the coin with the respect to the ground.