Solution Found!
The Force Exerted on the Moon Figure 5-27 shows the Earth,
Chapter 5, Problem 35P(choose chapter or problem)
The Force Exerted on the Moon Figure 5-27 shows the Earth, Moon, and Sun (not to scale) in their relative positions at the time when the Moon is in its third-quarter phase. Though few people realize it, the force exerted on the Moon by the Sun is actually greater than the force exerted on the Moon by the Earth. In fact, the force exerted on the Moon by the Sun has a magnitude of \(F_\mathrm {SM}=4.34 \times 10^{20}\ \mathrm N\), whereas the force exerted by the Earth has a magnitude of only \(F_{\mathrm {EM}}=1.98 \times 10^{20}\ \mathrm N\). These forces are indicated to scale in Figure Find a) the direction and (b) the magnitude of the net force acting on the Moon. (c) Given that the mass of the Moon is \(M_{\mathrm M}=7.35 \times 10^{22}\ \mathrm {kg}\), find the magnitude of its acceleration at the time of the third quarter phase.
Equation Transcription:
Text Transcription:
F_{SM}=4.34x10^20 N
F_{EM}=1.98x10^20 N
M_{M}=7.35x10^22 kg
Questions & Answers
QUESTION:
The Force Exerted on the Moon Figure 5-27 shows the Earth, Moon, and Sun (not to scale) in their relative positions at the time when the Moon is in its third-quarter phase. Though few people realize it, the force exerted on the Moon by the Sun is actually greater than the force exerted on the Moon by the Earth. In fact, the force exerted on the Moon by the Sun has a magnitude of \(F_\mathrm {SM}=4.34 \times 10^{20}\ \mathrm N\), whereas the force exerted by the Earth has a magnitude of only \(F_{\mathrm {EM}}=1.98 \times 10^{20}\ \mathrm N\). These forces are indicated to scale in Figure Find a) the direction and (b) the magnitude of the net force acting on the Moon. (c) Given that the mass of the Moon is \(M_{\mathrm M}=7.35 \times 10^{22}\ \mathrm {kg}\), find the magnitude of its acceleration at the time of the third quarter phase.
Equation Transcription:
Text Transcription:
F_{SM}=4.34x10^20 N
F_{EM}=1.98x10^20 N
M_{M}=7.35x10^22 kg
ANSWER:
Step 1 of 4
Here we have to calculate the direction and magnitude of the net force acting on the moon. Also, we have to calculate the magnitude of the acceleration at the time of third quadrant stage.
It is given that, the force exerted by Sun on Moon is and the force exerted by the Earth on Moon is as shown in the figure below.