An object of mass m = 5.95 kg has an acceleration . Three

QUESTION:

An object of mass \(m=5.95\ \mathrm {kg}\) has an acceleration \(\mathrm {\vec{a}=(1.17\ m/s^2)\hat{x}+(-0.664\ m/s^2)\hat{y}}\). Three forces act on this object: \(\mathrm {\vec{F}_1}\), \(\mathrm {\vec{F}_2}\), and \(\mathrm {\vec{F}_3}\). Given that \(\mathrm {\vec{F}_1=(3.22\ N)\hat{x}}\) and \(\mathrm {\vec{F}_2=(-1.55\ N)\hat{x}+(2.05\ N)\hat{y}}\), find \(\(\mathrm {\vec{F}_3}\)\).

Equation Transcription:

Text Transcription:

m=5.95 kg

vec{a}=(1.17 m/s^2)hat{x}+(-0.664 m/s^2)hat{y}

vec{F}_1

vec{F}_2

vec{F}_3

vec{F}_1=(3.22 N)hat{x}

vec{F}_2=(-1.55 N)hat{x}+(2.05 N)hat{y}

vec{F}_3