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A pendulum bob with a mass of 0.13 kg is attached to a

Chapter 8, Problem 73GP

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QUESTION:

Problem 73GP

A pendulum bob with a mass of 0.13 kg is attached to a string with a length of 0.95 m. We choose the potential energy to be zero when the string makes an angle of 90° with the vertical. (a) Find the potential energy of this system when the string makes an angle of 45° with the vertical. (b) Is the magnitude of the change in potential energy from an angle of 90° to 45° greater than, less than, or the same as the magnitude of the change from 45° to 0°? Explain. (c) Calculate the potential energy of the system when the string is vertical.

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QUESTION:

Problem 73GP

A pendulum bob with a mass of 0.13 kg is attached to a string with a length of 0.95 m. We choose the potential energy to be zero when the string makes an angle of 90° with the vertical. (a) Find the potential energy of this system when the string makes an angle of 45° with the vertical. (b) Is the magnitude of the change in potential energy from an angle of 90° to 45° greater than, less than, or the same as the magnitude of the change from 45° to 0°? Explain. (c) Calculate the potential energy of the system when the string is vertical.

ANSWER:

Step 1 of 4

Part (a)

A pendulum bob is attached to the string of length L. The potential energy at the mean position ( with the vertical) of the bob is considered to be zero. We are going to find the change in potential energy of the bob when the string makes an angle  with the vertical.

The mass of the bob m = 0.13 kg

The acceleration due to gravity

The length of the string L = 0.95 m

The angle

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