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An ice cube is placed on top of an overturned spherical
Chapter 8, Problem 93GP(choose chapter or problem)
An ice cube is placed on top of an overturned spherical bowl of radius r, as indicated in Figure 8–30. If the ice cube slides downward from rest at the top of the bowl, at what angle does
it separate from the bowl? In other words, at what angle does the normal force between the ice cube and the bowl go to zero?
Equation Transcription:
Text Transcription:
theta
Questions & Answers
QUESTION:
An ice cube is placed on top of an overturned spherical bowl of radius r, as indicated in Figure 8–30. If the ice cube slides downward from rest at the top of the bowl, at what angle does
it separate from the bowl? In other words, at what angle does the normal force between the ice cube and the bowl go to zero?
Equation Transcription:
Text Transcription:
theta
ANSWER:
Solution 93GP
Step 1 of 3
We have to find the angle at which the normal force between the ice cube and the bowl goes to zero.
The angle at which the normal force() between the ice cube and the bowl goes to zero can be found by applying Newton’s second law in the radial direction at
.
. . . . . (i)
where,
mass of the ice cube
speed of ice cube at the point