Problem 25P

When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4440 rpm to 0.00 rpm in 2.50 s. (a) What is the angular acceleration of the blade? (b) What is the distance traveled by a point on the rim of the blade during the deceleration? (c) What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?

Solution 25P

Step 1 of 3

Part a

We are required to calculate the angular acceleration of the of the blade.

Given data:

Initial angular speed rpm

rad/m

rad/s

rad/s

Final angular speed rpm

rad/s

Time taken to reach 0 rad/s s

Therefore, the angular acceleration,

(rad/s)/s

rad/s2

rev/s2

rev/s2

Therefore, the angular acceleration is -29.6 rev/s2.