A stick with a mass of 0.214 kg and a length of 0.436 m rests in contact with a bowling ball and a rough floor, as shown in. The bowling ball has a diameter of 21.6 cm, and the angle the stick makes with the horizontal is 30.0°. You may assume there is no friction between the stick and the bowling ball, though friction with the floor must be taken into account. (a) Find the magnitude of the force exerted on the stick by the bowling ball. (b) Find the horizontal component of the force exerted on the stick by the floor. (c) Repeat part (b) for the vertical component of the force.
Step 1 of 5:
Consider a stick rests on a bowling ball and rough floor. There is no friction between the ball and the stick but a considerable amount of friction is there between the stick and the floor. We are going to find the magnitude of the force on the stick by the ball. The force is nothing but the normal force.
The mass of the stick m = 0.214 kg
Length of the stick L = 0.436 m
The diameter of the ball (2r) = 21.6 cm or 0.216 m
The angle θ = 30°
The weight of the stick W = mg (g = 9.8 m/s2)