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Physics / Physics with MasteringPhysics 4 / Chapter 12 / Problem 48P

Physics with MasteringPhysics | 4th Edition | ISBN: 9780321541635 | Authors: James S. Walker

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Chapter 12, Problem 48P

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QUESTION:

Problem 48P

Suppose one of the Global Positioning System satellites has a speed of 4.46 km/s at perigee and a speed of 3.64 km/s at apogee. If the distance from the center of the Earth to the satellite at perigee is 2.00 × 104 lem, what is the corresponding distance at apogee?

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QUESTION:

Problem 48P

Suppose one of the Global Positioning System satellites has a speed of 4.46 km/s at perigee and a speed of 3.64 km/s at apogee. If the distance from the center of the Earth to the satellite at perigee is 2.00 × 104 lem, what is the corresponding distance at apogee?

ANSWER:

Step 1 of 2:

In this question, we need to find the distance from to center of Earth to apogee

Data given

Speed of rocket at perigee ${v}_{p}=4.4\ km/s$

Speed to rocket at apogee ${v}_{a}=3.64\ km/s$

Distance from Earth to perigee ${r}_{p}=2.00\times{}1{0}^{4}\ km$

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