Solution: The plates of a parallel-plate capacitor are 2.50
Chapter 24, Problem 24.1(choose chapter or problem)
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in vacuum. The electric field between the plates has a magnitude of \(4.00 \times 10^6\mathrm{\ V}/\mathrm{m}\). What is (a) the potential difference between the plates; (b) the area of each plate; (c) the capacitance?
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer