When a resistor with resistance R is connected to a 1.50-V

University Physics with Modern Physics (1) | 14th Edition | ISBN: 9780321973610 | Authors: Hugh D. Young Roger A. Freedman

ISBN: 9780321973610 228

Solution for problem 25.34 Chapter 25

University Physics with Modern Physics (1) | 14th Edition

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Problem 25.34

When a resistor with resistance R is connected to a 1.50-V flashlight battery, the resistor consumes 0.0625 W of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a 12.6-V car battery? Assume that R remains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes 5.00 W. What is the voltage of this battery?

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Chapter 25, Problem 25.34 is Solved

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Textbook: University Physics with Modern Physics (1)

Edition: 14

Author: Hugh D. Young Roger A. Freedman

ISBN: 9780321973610

University Physics with Modern Physics (1) was written by and is associated to the ISBN: 9780321973610. This textbook survival guide was created for the textbook: University Physics with Modern Physics (1), edition: 14. This full solution covers the following key subjects: . This expansive textbook survival guide covers 44 chapters, and 4574 solutions. The answer to “When a resistor with resistance R is connected to a 1.50-V flashlight battery, the resistor consumes 0.0625 W of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a 12.6-V car battery? Assume that R remains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes 5.00 W. What is the voltage of this battery?” is broken down into a number of easy to follow steps, and 75 words. Since the solution to 25.34 from 25 chapter was answered, more than 436 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 25.34 from chapter: 25 was answered by , our top Physics solution expert on 01/09/18, 07:46PM.