An electron moves horizontally across the Earths equator
Chapter 29, Problem 9(choose chapter or problem)
An electron moves horizontally across the Earths equator at a speed of 2.50 3 106 m/s and in a direction 35.08 N of E. At this point, the Earths magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 3 1025 T. What is the force acting on the electron due to its interaction with the Earths magnetic field? (a) 6.88 3 10218 N due west (b) 6.88 3 10218 N toward the Earths surface (c) 9.83 3 10218 N toward the Earths surface (d) 9.83 3 10218 N away from the Earths surface (e) 4.00 3 10218 N away from the Earths surface
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer