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Calculating Ion Path Radius in a Mass Spectrometer: Electric vs Magnet
Chapter 29, Problem 25(choose chapter or problem)
Consider the mass spectrometer shown schematically in Figure 29.14. The magnitude of the electric field between the plates of the velocity selector is \(2.50 \times 10^3 \ \mathrm{V} / \mathrm{m}\), and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.035 0 T. Calculate the radius of the path for a singly charged ion having a mass \(m=2.18 \times 10^{-26} \mathrm{~kg}\).
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QUESTION:
Consider the mass spectrometer shown schematically in Figure 29.14. The magnitude of the electric field between the plates of the velocity selector is \(2.50 \times 10^3 \ \mathrm{V} / \mathrm{m}\), and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.035 0 T. Calculate the radius of the path for a singly charged ion having a mass \(m=2.18 \times 10^{-26} \mathrm{~kg}\).
ANSWER:Step 1 of 2
Given data:
Consider the mass spectrometer shown schematically in Figure 29.14.
The magnitude of the electric field between the plates of the velocity selector is \(\mathrm{E}=2.50 \times 10^{3} \mathrm{~V} / \mathrm{m}\).
The magnetic field in the velocity selector and the deflection chamber has a magnitude of B = 0.0350 T.
The singly charged ion has a mass of \(\mathrm{m}=2.18 \times 10^{-26} \mathrm{~kg}\).
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Calculating Ion Path Radius in a Mass Spectrometer: Electric vs Magnet
Want To Learn More? To watch the entire video and ALL of the videos in the series:
Explore how a mass spectrometer works by analyzing an ion's path through the device. Understand the relationship between electric and magnetic fields in determining the ion's trajectory. Learn to compute the radius of an ion's path within the mass spectrometer.