A 0.22-μF capacitor is charged by a 1.5-V battery. After being charged, the capacitor is connected to a small electric motor. Assuming 100% efficiency, (a) to what height can the motor lift a 5.0-g mass? (b) What initial voltage must the capacitor have if it is to lift a 5.0-g mass through a height of 1.0 cm?

Solution 66 P:

Step 1 of 2:-

a)

Here, we have to find the height upto which the motor can lift the 5 kg mass.

The capacitance of the capacitor is,

.

The potential difference by the battery is,

.

The electric motor is having 100% efficiency.

The energy stored in the capacitor is,

.

The mass to be lifted is,

As, the motor connected to the capacitor will lift the mass, the energy stored in the capacitor will be converted to the gravitational potential energy.

So,

.

So, the mass will be lifted to a height of .