×
Log in to StudySoup
Get Full Access to Precalculus Enhanced With Graphing Utilities - 6 Edition - Chapter A.1 - Problem 2
Join StudySoup for FREE
Get Full Access to Precalculus Enhanced With Graphing Utilities - 6 Edition - Chapter A.1 - Problem 2

Already have an account? Login here
×
Reset your password

Answer: On the real number line, the real number zero is

Precalculus Enhanced with Graphing Utilities | 6th Edition | ISBN: 9780132854351 | Authors: Michael Sullivan ISBN: 9780132854351 232

Solution for problem 2 Chapter A.1

Precalculus Enhanced with Graphing Utilities | 6th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Precalculus Enhanced with Graphing Utilities | 6th Edition | ISBN: 9780132854351 | Authors: Michael Sullivan

Precalculus Enhanced with Graphing Utilities | 6th Edition

4 5 1 370 Reviews
30
1
Problem 2

On the real number line, the real number zero is the coordinate of the .

Step-by-Step Solution:
Step 1 of 3

Homework 9 Calder Sheagren 1 a) Claim: f : R ! R;f(x) = 17 is continuous at x = 9: 0 Proof. Take an arbitrary ▯ > 0. Let ▯ = ▯. Then, for all jx ▯ x j < ▯; jf(x) ▯ f(x )j = 0 0 j17 ▯ 17j = 0 < ▯ = ▯. b) Claim: g : R ! R;g(x) = x is continuous at x = 9: 0 Proof. Take an arbitrary ▯ > 0. Let ▯ = ▯. Then, for all jx ▯ x j < ▯; jg(0) ▯ g(x )j = 0 jx ▯ 9j < ▯ = ▯. 2 c) Claim: h : R ! R;h(x) = x + 2 is continuous at x = 9: 0 2 Proof. Take an arbitrary ▯ > 0. Let ▯ = ▯ +18▯. Then, for all jx▯x j < ▯; j

Step 2 of 3

Chapter A.1, Problem 2 is Solved
Step 3 of 3

Textbook: Precalculus Enhanced with Graphing Utilities
Edition: 6
Author: Michael Sullivan
ISBN: 9780132854351

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Answer: On the real number line, the real number zero is