For each value of p > 1, let c(p) = x=1 1 xp . Suppose
Chapter 3, Problem 6(choose chapter or problem)
For each value of p > 1, let c(p) = x=1 1 xp . Suppose that the random variable X has a discrete distribution with the following p.f.: f (x) = 1 c(p)xp for x = 1, 2,.... a. For each fixed positive integer n, determine the probability that X will be divisible by n. b. Determine the probability that X will be odd.
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