The solution to Exercise 1 of Sec. 3.9 is the p.d.f. of X1
Chapter 6, Problem 1(choose chapter or problem)
The solution to Exercise 1 of Sec. 3.9 is the p.d.f. of X1 + X2 in Example 6.1.2. Find the p.d.f. of X2 = (X1 + X2)/2. Compare the probabilities that X2 and X1 are close to 0.5. In particular, compute Pr(|X2 0.5| < 0.1) and Pr(|X1 0.5| < 0.1). What feature of the p.d.f. of X2 makes it clear that the distribution is more concentrated near the mean?
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