In a three-way layout with one observation in each cell,

Chapter 11, Problem 23

(choose chapter or problem)

In a three-way layout with one observation in each cell, the observations Yijk (i = 1,...,I ; j = 1,...,J ; k = 1,...,K) are assumed to be independent and normally distributed, with a common variance 2. Suppose that E(Yijk) = ijk. Show that for every set of numbers ijk, there exists a unique set of numbers , A i , B j , C k , AB ij , AC ik , BC jk , and ijk (i = 1,...,I ; j = 1,...,J ; k = 1,...,K) such that A + = B + = C + = 0, AB i+ = AB +j = AC i+ = AC +k = BC j+ = BC +k = 0, ij+ = i+k = +jk = 0, and ijk = + A i + B j + C k + AB ij + AC ik + BC jk + ijk, for all values of i, j , and k

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back