IP In Conceptual Checkpoint 29-2 we considered an
Chapter 29, Problem 90GP(choose chapter or problem)
The rest energy, \(m_{0} c^{2}\), of a particle with a kinetic energy and a momentum
can be determined as follows:
\(m_{0} c^{2}=\frac{(p c)^{2}-K^{2}}{2 K}\)
Suppose a pion (a subatomic particle) is observed to have a kinetic energy \(K=35.0 \mathrm{MeV}\) and a momentum \(p=5.61 \times 10^{-20} \mathrm{~kg}^{3} \mathrm{~m} / \mathrm{s}=105 \mathrm{MeV} / \mathrm{c}\). What is the rest energy of the pion?
Give your answer in .
Equation Transcription:
Text Transcription:
m0c2
m0c2=(pc)2 - K2 over 2K
K=35.0MeV
p=5.61 x 10-20 kg3 m/s=105MeV/c
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