Problem 21P
The work function of gold is 4.58 eV. What frequency of light must be used to eject electrons from a gold surface with a maximum kinetic energy of 6.48 × 10−19 J?
Step-by-Step Solution:
Solution 21 P:
Step 1 of 1:-
Here, we have to find the frequency of the incident light which will emit the electrons with a maximum kinetic energy of .
Given that,
.
From the equation of photoelectric effect,
So, the frequency of incident photon is .
Step 2 of 1
