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Applied Statistics and Probability for Engineers | 6th Edition | ISBN: 9781118539712 | Authors: Douglas C. Montgomery, George C. Runger
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A researcher receives 100 containers of oxygen. Of those

Chapter 2, Problem 191SE

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QUESTION:

A researcher receives 100 containers of oxygen. Of those containers, 20 have oxygen that is not ionized, and the rest are ionized. Two samples are randomly selected, without replacement, from the lot.

(a) What is the probability that the first one selected is not ionized?

(b) What is the probability that the second one selected is not ionized given that the first one was ionized?

(c) What is the probability that both are ionized?

(d) How does the answer in part (b) change if samples selected were replaced prior to the next selection?

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QUESTION:

A researcher receives 100 containers of oxygen. Of those containers, 20 have oxygen that is not ionized, and the rest are ionized. Two samples are randomly selected, without replacement, from the lot.

(a) What is the probability that the first one selected is not ionized?

(b) What is the probability that the second one selected is not ionized given that the first one was ionized?

(c) What is the probability that both are ionized?

(d) How does the answer in part (b) change if samples selected were replaced prior to the next selection?

ANSWER:

Step 1 of 4

From the given information we know that the total containers of oxygen is 100.

Then the total non ionized containers is 20 and the total ionized containers is 100-20 = 80.

a). Now we need to find the probability of the first one is not ionized.

The probability of the first one is not ionized is

P(first one is not ionized) =

P(first one is not ionized) =

P(first one is not ionized) = 0.20

Therefore, the probability of the first one is not ionized is 0.20.

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