Orders arrive at a Web site according to a Poisson process

Chapter 3, Problem 172E

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QUESTION:

Problem 172E

Orders arrive at a Web site according to a Poisson process with a mean of 12 per hour. Determine the following:

(a) Probability of no orders in five minutes.

(b) Probability of 3 or more orders in five minutes.

(c) Length of a time interval such that the probability of no orders in an interval of this length is 0.001.

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QUESTION:

Problem 172E

Orders arrive at a Web site according to a Poisson process with a mean of 12 per hour. Determine the following:

(a) Probability of no orders in five minutes.

(b) Probability of 3 or more orders in five minutes.

(c) Length of a time interval such that the probability of no orders in an interval of this length is 0.001.

ANSWER:

Solution :

Step 1 of 3:

Given for an interval of the length of time T with the parameter .

We know that from the mean number of orders arrive at a website per hour are 12.

So .

Then the poisson variable X’s probability function is

P(X=x) =  

Our goal is:

a). We need to find the probability of no orders in 5 minutes.

b). We need to find the probability of 3 or more in 5 minutes.

c). We need to find the probability of no orders in an interval of this length is 0.001.

a). Now we have to find the probability of no orders in 5 minutes.

We know that .

Then,

 

1

Probability of getting no orders, so P(X=0).

P(X=0) = 

P(X=0) =

P(X=0) = 0.367

Therefore, the probability of no orders in 5 minutes is 0.3678.


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