Solution Found!
Determine the mean and variance of the random
Chapter 4, Problem 42E(choose chapter or problem)
Determine the mean and variance of the random variable in Exercise 4-14.
4-14. The distribution of X is approximated with a triangular probability density function \(f(x)=0.025 x-0.0375\) for 30 < x < 50 and \(f(x)=-0.025 x+0.0875\) for 50 < x < 70. Determine the following:
\(P(X \leq 40)\)\(P(40<X \leq 60)\)Value x exceeded with probability 0.99Equation transcription:
Text transcription:
f(x)=0.025 x-0.0375
f(x)=-0.025 x+0.0875
P(X \leq 40)
P(40<X \leq 60)
Questions & Answers
QUESTION:
Determine the mean and variance of the random variable in Exercise 4-14.
4-14. The distribution of X is approximated with a triangular probability density function \(f(x)=0.025 x-0.0375\) for 30 < x < 50 and \(f(x)=-0.025 x+0.0875\) for 50 < x < 70. Determine the following:
\(P(X \leq 40)\)\(P(40<X \leq 60)\)Value x exceeded with probability 0.99Equation transcription:
Text transcription:
f(x)=0.025 x-0.0375
f(x)=-0.025 x+0.0875
P(X \leq 40)
P(40<X \leq 60)
ANSWER:Solution
Step 1 of 2
We have to find the mean and variance of the random variable
The given probability density function is
=
Mean=
=
=
=
=786.667-1711.67
= -925.003