Solution Found!
The life of a recirculating pump follows a Weibull
Chapter 4, Problem 201SE(choose chapter or problem)
The life of a recirculating pump follows a Weibull distribution with parameters \(\beta=2\) and \(\delta=700\) hours. Determine for parts (a) and (b):
(a) Mean life of a pump (b) Variance of the life of a pump
(c) What is the probability that a pump will last longer than its mean?
Equation transcription:
Text transcription:
\beta=2
\delta=700
Questions & Answers
QUESTION:
The life of a recirculating pump follows a Weibull distribution with parameters \(\beta=2\) and \(\delta=700\) hours. Determine for parts (a) and (b):
(a) Mean life of a pump (b) Variance of the life of a pump
(c) What is the probability that a pump will last longer than its mean?
Equation transcription:
Text transcription:
\beta=2
\delta=700
ANSWER:Solution:
Step 1 of 3:
It is given that the life of a recirculating pump is is a random variable and has the Weibull distribution with and
hours.
Using this we need to find the required values.