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Among homeowners in a metropolitan area, 25% recycle paper
Chapter 4, Problem 223SE(choose chapter or problem)
Problem 223SE
Among homeowners in a metropolitan area, 25% recycle paper each week. A waste management company services 10,000 homeowners (assumed independent). Approximate the following probabilities:
(a) More than 2600 recycle paper in a week
(b) Between 2400 and 2600 recycle paper in a week
(c) Number of customers who recycle paper in a week that is exceeded with probability approximately 0.05
Questions & Answers
QUESTION:
Problem 223SE
Among homeowners in a metropolitan area, 25% recycle paper each week. A waste management company services 10,000 homeowners (assumed independent). Approximate the following probabilities:
(a) More than 2600 recycle paper in a week
(b) Between 2400 and 2600 recycle paper in a week
(c) Number of customers who recycle paper in a week that is exceeded with probability approximately 0.05
ANSWER:
Solution :
Step 1 of 3:
Let X denotes the number of customers who recycle paper in a week.
Let p denotes the probability that the recycle paper in a week is 0.25 and
Let n denotes the total number of house owners is 10000.
Here we can use normal approximation.
Z =
Where,
np = 10000(0.25) = 2500 and
n(1-p) = 10000(1-0.25)
n(1-p) = 10000 (0.75)
n(1-p) = 7500
Our goal is:
a). We need to find the probability that the more than 2600 recycle paper in a week.
b). We need to find the probability that the between 2400 and 2600 recycle paper in a week .
d). We need to find the number of customers who recycle paper in a week.
a). The probability that the more than 2600 recycle paper in a week is
P(X>2600) = P
P(X>2600) = P
P(X>2600) = P
P(X>2600) = 1-
Using areas under the normal curve table,
P(X>2600) = 1-0.9899
P(X>2600) = 0.0101
Therefore, the probability that the more than 2600 recycle paper in a week is 0.0101.