Solution Found!
Data for tire life was described in Exercise 8-29. The
Chapter 9, Problem 87E(choose chapter or problem)
Data for tire life was described in Exercise 8-29. The sample standard deviation was kilometers and \(n=16\).
(a) Can you conclude, using \(\alpha=0.05\), that the standard deviation of tire life is less than 4000 kilometers? State any necessary assumptions about the underlying distribution of the data. Find the -value for this test.
(b) Explain how you could answer the question in part (a) by constructing a one-sided confidence interval for \(\sigma\).
Equation Transcription:
Text Transcription:
n=16
alpha=0.05
sigma
Questions & Answers
QUESTION:
Data for tire life was described in Exercise 8-29. The sample standard deviation was kilometers and \(n=16\).
(a) Can you conclude, using \(\alpha=0.05\), that the standard deviation of tire life is less than 4000 kilometers? State any necessary assumptions about the underlying distribution of the data. Find the -value for this test.
(b) Explain how you could answer the question in part (a) by constructing a one-sided confidence interval for \(\sigma\).
Equation Transcription:
Text Transcription:
n=16
alpha=0.05
sigma
ANSWER:
Step 1 of 2
=sample standard deviation=3285 kilometers
a) No, you cannot conclude that the standard deviation of tire life is less than 4000 kilometers with alpha=0.05. The assumption for this test is that the underlying distribution of the data is normal. The -value for this test is not calculable with the given information.