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Consider the lengths of stay at a hospital’s emergency
Chapter 3, Problem 111E(choose chapter or problem)
Problem 111E
Consider the lengths of stay at a hospital’s emergency department in Exercise 3-33. Assume that five persons independently arrive for service.
(a) What is the probability that the length of stay of exactly one person is less than or equal to 4 hours?
(b) What is the probability that exactly two people wait more than 4 hours?
(c) What is the probability that at least one person waits more than 4 hours?
3-33. Actual lenghts of stay at a hospitat’s emergency depament in 20009 are shown in the following table (rounded to the nearest hour. Length of stay is the total of wait and service times. Some longer stays are also approximated as 15 hours in this table.
Hours |
Count |
Percent |
1 |
19 |
3.80 |
2 |
51 |
10.20 |
3 |
86 |
17.20 |
4 |
102 |
20.40 |
5 |
87 |
17.40 |
6 |
62 |
12.40 |
7 |
40 |
8.00 |
8 |
18 |
3.60 |
9 |
14 |
2.80 |
10 |
11 |
2.20 |
15 |
10 |
2.00 |
Calculate the probability mass function of the wait time for service.
Questions & Answers
QUESTION:
Problem 111E
Consider the lengths of stay at a hospital’s emergency department in Exercise 3-33. Assume that five persons independently arrive for service.
(a) What is the probability that the length of stay of exactly one person is less than or equal to 4 hours?
(b) What is the probability that exactly two people wait more than 4 hours?
(c) What is the probability that at least one person waits more than 4 hours?
3-33. Actual lenghts of stay at a hospitat’s emergency depament in 20009 are shown in the following table (rounded to the nearest hour. Length of stay is the total of wait and service times. Some longer stays are also approximated as 15 hours in this table.
Hours |
Count |
Percent |
1 |
19 |
3.80 |
2 |
51 |
10.20 |
3 |
86 |
17.20 |
4 |
102 |
20.40 |
5 |
87 |
17.40 |
6 |
62 |
12.40 |
7 |
40 |
8.00 |
8 |
18 |
3.60 |
9 |
14 |
2.80 |
10 |
11 |
2.20 |
15 |
10 |
2.00 |
Calculate the probability mass function of the wait time for service.
ANSWER: