An insulated rigid tank is divided into two compartments

Chapter 4, Problem 140P

(choose chapter or problem)

An insulated rigid tank is divided into two compartments of different volumes. Initially, each compartment contains the same ideal gas at identical pressure but at different temperatures and masses. The wall separating the two compartments is removed and the two gases are allowed to mix. Assuming constant specific heats, find the simplest expression for the mixture temperature written in the form

\(T_{3}=f\left(\frac{m_{1}}{m_{3}}, \frac{m_{2}}{m_{3}}, T_{1}, T_{2}\right)\)

where \(m_{3}\) and \(T_{3}\) are the mass and temperature of the final mixture, respectively.

Equation Transcription:

Text Transcription:

T_3=f(m_1/m_3,m_2/m_3,T_1,T_2)

m_3

T_3

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back