Solution Found!
A Carnot heat pump is to be used to heat a house and
Chapter 6, Problem 104P(choose chapter or problem)
A Carnot heat pump is to be used to heat a house and maintain it at \(25^{\circ} \mathrm{C}\) in winter. On a day when the average outdoor temperature remains at about \(2^{\circ} \mathrm{C}\), the house is estimated to lose heat at a rate of \(55,000 \mathrm{~kJ} / \mathrm{h}\). If the heat pump consumes \(4.8 \mathrm{~kW}\) of power while operating, determine (a) how long the heat pump ran on that day; (b) the total heating costs, assuming an average price of \(11 \mathrm{c} / \mathrm{kWh}\) for electricity; and (c) the heating cost for the same day if resistance heat-ing is used instead of a heat pump.
Equation Transcription:
25°C
2°C
4.8 kW
Text Transcription:
25 degree celsius
2 degree celsius
4.8 kW
55,000 kJ/h
11¢/kWh
Questions & Answers
QUESTION:
A Carnot heat pump is to be used to heat a house and maintain it at \(25^{\circ} \mathrm{C}\) in winter. On a day when the average outdoor temperature remains at about \(2^{\circ} \mathrm{C}\), the house is estimated to lose heat at a rate of \(55,000 \mathrm{~kJ} / \mathrm{h}\). If the heat pump consumes \(4.8 \mathrm{~kW}\) of power while operating, determine (a) how long the heat pump ran on that day; (b) the total heating costs, assuming an average price of \(11 \mathrm{c} / \mathrm{kWh}\) for electricity; and (c) the heating cost for the same day if resistance heat-ing is used instead of a heat pump.
Equation Transcription:
25°C
2°C
4.8 kW
Text Transcription:
25 degree celsius
2 degree celsius
4.8 kW
55,000 kJ/h
11¢/kWh
ANSWER:
Step 1 of 5
Part (a)
The equation for the COP of heat pump is as follows:
For , and .