Solution Found!
It is often stated that the refrigerator door should be
Chapter 6, Problem 118P(choose chapter or problem)
It is often stated that the refrigerator door should be opened as few times as possible for the shortest duration of time to save energy. Consider a household refrigerator whose interior volume is \(0.9 \mathrm{~m}^{3}\) and average internal temperature is \(4^{\circ} \mathrm{C}\). At any given time, one-third of the refrigerated space is occupied by food items, and the remaining \(0.6 \mathrm{~m}^{3}\) is filled with air. The average temperature and pressure in the kitchen are \(20^{\circ} \mathrm{C}\) and \(95 \mathrm{kPa}\), respectively. Also, the moisture contents of the air in the kitchen and the refrigerator are \(0.010\) and \(0.004 \mathrm{~kg}\) per \(\mathrm{kg}\) of air, respectively, and thus \(0.006 \mathrm{~kg}\) of water vapor is condensed and removed for each \(\mathrm{kg}\) of air that enters. The refrigerator door is opened an average of 20 times a day, and each time half of the air volume in the refrigerator is replaced by the warmer kitchen air. If the refrigerator has a coefficient of performance of \(1.4\) and the cost of electricity is \(11.5\) cents per \(\mathrm{kWh}\), determine the cost of the energy wasted per year as a result of opening the refrigerator door. What would your answer be if the kitchen air were very dry and thus a negligible amount of water vapor condensed in the refrigerator?
Equation Transcription:
4°C
20°C
Text Transcription:
4 degree celsius
0.9 m^3
20 degree celsius
95 kPa
0.004 kg
0.006 kg
Questions & Answers
QUESTION:
It is often stated that the refrigerator door should be opened as few times as possible for the shortest duration of time to save energy. Consider a household refrigerator whose interior volume is \(0.9 \mathrm{~m}^{3}\) and average internal temperature is \(4^{\circ} \mathrm{C}\). At any given time, one-third of the refrigerated space is occupied by food items, and the remaining \(0.6 \mathrm{~m}^{3}\) is filled with air. The average temperature and pressure in the kitchen are \(20^{\circ} \mathrm{C}\) and \(95 \mathrm{kPa}\), respectively. Also, the moisture contents of the air in the kitchen and the refrigerator are \(0.010\) and \(0.004 \mathrm{~kg}\) per \(\mathrm{kg}\) of air, respectively, and thus \(0.006 \mathrm{~kg}\) of water vapor is condensed and removed for each \(\mathrm{kg}\) of air that enters. The refrigerator door is opened an average of 20 times a day, and each time half of the air volume in the refrigerator is replaced by the warmer kitchen air. If the refrigerator has a coefficient of performance of \(1.4\) and the cost of electricity is \(11.5\) cents per \(\mathrm{kWh}\), determine the cost of the energy wasted per year as a result of opening the refrigerator door. What would your answer be if the kitchen air were very dry and thus a negligible amount of water vapor condensed in the refrigerator?
Equation Transcription:
4°C
20°C
Text Transcription:
4 degree celsius
0.9 m^3
20 degree celsius
95 kPa
0.004 kg
0.006 kg
ANSWER:
Step 1 of 4
The gas constant of air is.
The specific heat at constant pressure is.
The volume of refrigerated air replaced each time when the refrigerator is open is given by,
For,, the volume of air,
The total volume of air replaced by the room air per year is,