Solution Found!
Refrigerant-134a enters an adiabatic compressor at –30°C
Chapter 8, Problem 62P(choose chapter or problem)
Refrigerant-134a enters an adiabatic compressor at \(-30^{\circ} \mathrm{C}\) as a saturated vapor at a rate of \(0.45 \mathrm{~m}^{3} / \mathrm{min}\) and leaves at and \(55^{\circ} \mathrm{C}\). Determine
the power input to the compressor,
(b) the isentropic efficiency of the compressor, and the rate of exergy destruction and the second-law efficiency of the compressor. Take \(T_{0}=27^{\circ} \mathrm{C}\)
Equation Transcription:
Text Transcription:
-30°C
0.45 m3/min
55°C
T0=27°C
Questions & Answers
QUESTION:
Refrigerant-134a enters an adiabatic compressor at \(-30^{\circ} \mathrm{C}\) as a saturated vapor at a rate of \(0.45 \mathrm{~m}^{3} / \mathrm{min}\) and leaves at and \(55^{\circ} \mathrm{C}\). Determine
the power input to the compressor,
(b) the isentropic efficiency of the compressor, and the rate of exergy destruction and the second-law efficiency of the compressor. Take \(T_{0}=27^{\circ} \mathrm{C}\)
Equation Transcription:
Text Transcription:
-30°C
0.45 m3/min
55°C
T0=27°C
ANSWER:
Step by step solution Step 1 of 13(a)From saturated refrigerant- 134a--temperature table, write the properties ofrefrigerant-134a at an initial temperature of and an initial quality of as, , andHere, initial enthalpy of refrigerant is , initial entropy if refrigerant is, initial specificvolume is , enthalpy of saturated vapor is , entropy of saturated vapor is andspecific volume of saturated vapor isWrite the properties of refrigerant-134a from the table of “superheated refrigerant-134a table “asin table (1)\n -Here, final enthalpy is , final entropy is , final temperature is , and final pressure is .