Solved: The Inverse of a Matrix In Exercises 16, show that

Chapter 2, Problem 5

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In Exercises 1–6, show that B is the inverse of A.

\(A=\left[\begin{array}{rrr} -2 & 2 & 3 \\ 1 & -1 & 0 \\ 0 & 1 & 4 \end{array}\right], \quad B=\frac{1}{3}\left[\begin{array}{rrr} -4 & -5 & 3 \\ -4 & -8 & 3 \\= 1 & 2 & 0 \end{array}\right]  \)

Text Transcription:

A = [_0^1^-2 _1^-1^2 _4^0^3], B = 1/3[_1^-4^-4 _2^-8^-5 _0^3^3]

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