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Piecewise Continuous FunctionsAlthough we are
Chapter 5, Problem 16AAE(choose chapter or problem)
Problem 16AAE
Piecewise Continuous Functions
Although we are mainly interested in continuous functions, many functions in applications are piecewise continuous. A function ƒ(x) is piecewise continuous on a closed interval I if ƒ has only finitely many discontinuities in I, the limits
exist and are finite at every interior point of I, and the appropriate onesided limits exist and are finite at the endpoints of I. All piecewise continuous functions are integrable. The points of discontinuity subdivide I into open and half-open subintervals on which ƒ is continuous, and the limit criteria above guarantee that ƒ has a continuous extension to the closure of each subinterval. To integrate a piecewise continuous function, we integrate the individual extensions and add the results. The integral of
(Figure 5.32) over [-1, 3] is
FIGURE 5.32 Piecewise continuous functions like this are integrated piece by piece.
The Fundamental Theorem applies to piecewise continuous functions with the restriction that is expected to equal ƒ(x) only at values of x at which ƒ is continuous. There is a similar restriction on Leibniz’s Rule (see Exercises 31–38).
Graph the functions and integrate them over their domains.
Questions & Answers
QUESTION:
Problem 16AAE
Piecewise Continuous Functions
Although we are mainly interested in continuous functions, many functions in applications are piecewise continuous. A function ƒ(x) is piecewise continuous on a closed interval I if ƒ has only finitely many discontinuities in I, the limits
exist and are finite at every interior point of I, and the appropriate onesided limits exist and are finite at the endpoints of I. All piecewise continuous functions are integrable. The points of discontinuity subdivide I into open and half-open subintervals on which ƒ is continuous, and the limit criteria above guarantee that ƒ has a continuous extension to the closure of each subinterval. To integrate a piecewise continuous function, we integrate the individual extensions and add the results. The integral of
(Figure 5.32) over [-1, 3] is
FIGURE 5.32 Piecewise continuous functions like this are integrated piece by piece.
The Fundamental Theorem applies to piecewise continuous functions with the restriction that is expected to equal ƒ(x) only at values of x at which ƒ is continuous. There is a similar restriction on Leibniz’s Rule (see Exercises 31–38).
Graph the functions and integrate them over their domains.
ANSWER:
Solution:
Step 1 of 3:
In this question, we have to plot the graph of the function and integrate it.