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The U.S. population The U.S. Census Bureau keeps a running
Chapter 7, Problem 34E(choose chapter or problem)
Problem 34E
The U.S. population The U.S. Census Bureau keeps a running clock totaling the U.S. population. On September 20, 2012, the total was increasing at the rate of 1 person every 12 sec. The population figure for 8:11 P.M. EST on that day was 314,419,198.
a. Assuming exponential growth at a constant rate, find the rate constant for the population's growth (people per 365-day year).
b. At this rate, what will the U.S. population be at 8:11 P.M. EST on September 20, 2019?
Questions & Answers
QUESTION:
Problem 34E
The U.S. population The U.S. Census Bureau keeps a running clock totaling the U.S. population. On September 20, 2012, the total was increasing at the rate of 1 person every 12 sec. The population figure for 8:11 P.M. EST on that day was 314,419,198.
a. Assuming exponential growth at a constant rate, find the rate constant for the population's growth (people per 365-day year).
b. At this rate, what will the U.S. population be at 8:11 P.M. EST on September 20, 2019?
ANSWER:
SOLUTION:
Step 1 of 3:
In this question, the U.S. population The U.S. Census Bureau keeps a running clock totaling the U.S. population. On September 20, 2012, the total was increasing at the rate of 1 person every 12 sec. The population figure for 8:11 P.M. EST on that day was 314,419,198.
(a) Assuming exponential growth at a constant rate, find the rate constant for the population's growth (people per 365-day year). (b) At this rate, find the U.S. population be at 8:11 P.M. EST on September 20, 2019.