Let g(t) = u(t - n/k)f(t - n/k), where f(t) is the function of and k > O. Note that h(t)

Chapter 4, Problem 4.5.30

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Let g(t) = u(t - n/k)f(t - n/k), where f(t) is the function of and k > O. Note that h(t) = f(t) + g(t) is the full-wave rectification of sin kt shown in Fig. 4.S. 17. Hence deduce from that k ns {h(t)} = S 2 +k2 coth 2k

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