The equilibrium constant of the dissociation reaction H2 ?
Chapter 16, Problem 7P(choose chapter or problem)
The equilibrium constant of the dissociation reaction \(\mathrm{H}_{2} \rightarrow 2 \mathrm{H}\) at \(3000 \mathrm{~K}\) and \(1 \mathrm{~atm}\) is \(K_{P}\). Express the equilibrium constants of the following reactions at \(3000 \mathrm{~K}\)in terms of \(K_{P_{1}}\) :
(a) \(\mathrm{H}_{2} \rightleftharpoons 2 \mathrm{H}\)
at \(2 \mathrm{~atm}\)
(b) \(\quad 2 \mathrm{H} \rightleftharpoons \mathrm{H}_{2}\)
at \(1 \mathrm{~atm}\)
(c) \(\quad 2 \mathrm{H}_{2} \rightleftharpoons 4 \mathrm{H}\)
(d) \(\mathrm{H}_{2}+2 \mathrm{~N}_{2} \rightleftharpoons 2 \mathrm{H}+2 \mathrm{~N}_{2} \quad\) at \(2 \mathrm{~atm}\)
(e) \(\quad 6 \mathrm{H} \rightleftharpoons 3 \mathrm{H}_{2} \quad\)at \(4 \mathrm{~atm}\)
Equation Transcription:
⇌
⇌
⇌
⇌
⇌
Text Transcription:
H_2 rightarrow 2H
s
3000 K
1 atm
K_P_1
3000 K
K_P_1
H_2 leftrightharpoons 2H 2 atm
2H leftrightharpoons H_2 1 atm
2H_2 leftrightharpoon 4H 1 atm
H_2+2N_2 leftrightharpoons 2H+2N_2 2 atm
6H leftrightharpoons 3H_2 4 atm
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer