Solution Found!
An oxygen molecule with mass m = M mo = 32 × 1.66 × 10?27
Chapter 1, Problem 88HP(choose chapter or problem)
Problem 88HP
An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?
Questions & Answers
QUESTION:
Problem 88HP
An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?
ANSWER:
Solution 88 HP:
Step 1 of 2:-
Here we have to calculate the kinetic energy of the molecule and the temperature too.
The mass of the oxygen molecule is, .
The speed of the molecule is, .
The kinetic energy of the molecule is,
.
.
The kinetic energy is .