An oxygen molecule with mass m = M mo = 32 × 1.66 × 10?27

Chapter 1, Problem 88HP

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QUESTION:

Problem 88HP

An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?

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QUESTION:

Problem 88HP

An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?

ANSWER:

Solution 88 HP:

Step 1 of 2:-

Here we have to calculate the kinetic energy of the molecule and the temperature too.

The mass of the oxygen molecule is, .

The speed of the molecule is, .

The kinetic energy of the molecule is,

.

   

    .

The kinetic energy is .

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