An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?
Solution 88 HP:
Step 1 of 2:-
Here we have to calculate the kinetic energy of the molecule and the temperature too.
The mass of the oxygen molecule is, .
The speed of the molecule is, .
The kinetic energy of the molecule is,
The kinetic energy is .