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A rigid tank is divided into two rooms, both containing
Chapter 3, Problem 210HP(choose chapter or problem)
Problem 210HP
A rigid tank is divided into two rooms, both containing water, by a membrane, as shown in Fig. P3.210. Room A is at 200 kPa, v = 0.5 m3/kg, VA = 1 m3, and room B contains 3.5 kg at 0.5 MPa, 400°C. The membrane now ruptures and heat transfer takes place so that the water comes to a uniform state at 100°C. Find the heat transfer during the process.
FIGURE P3.210
Questions & Answers
QUESTION:
Problem 210HP
A rigid tank is divided into two rooms, both containing water, by a membrane, as shown in Fig. P3.210. Room A is at 200 kPa, v = 0.5 m3/kg, VA = 1 m3, and room B contains 3.5 kg at 0.5 MPa, 400°C. The membrane now ruptures and heat transfer takes place so that the water comes to a uniform state at 100°C. Find the heat transfer during the process.
FIGURE P3.210
ANSWER:
Solution 210HP
Step 1 of 6
We have to find the heat transfer during the process.
The heat transfer can be found from the energy equation.
Where,
total mass of water in kg
internal energy of water at
uniform state of 100oC
mass of water in room
in kg
mass of water in room
=3.5 kg
internal energy of water at
200 kPa in kJ/kg
internal energy of water at
0.5 MPa, 400oC in kJ/kg
1W2 = Work done in the process in kJ