Solution Found!
An R410a heat pump cycle shown in Fig. P4.123 has an
Chapter 4, Problem 123HP(choose chapter or problem)
Problem 123HP
An R410a heat pump cycle shown in Fig. P4.123 has an R410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:
State 
1 
2 
3 
4 
5 
6 
P, kPa 
3100 
3050 
3000 
420 
400 
390 
T, °C 
120 
110 
45 

−10 
−5 
h, kJ/kg 
377 
367 
134 
— 
280 
284 
Calculate the heat transfer from the compressor, the heat transfer from the R410a in the condenser, and the heat transfer to the R410a in the evaporator.
FIGURE P4.123
Questions & Answers
QUESTION:
Problem 123HP
An R410a heat pump cycle shown in Fig. P4.123 has an R410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:
State 
1 
2 
3 
4 
5 
6 
P, kPa 
3100 
3050 
3000 
420 
400 
390 
T, °C 
120 
110 
45 

−10 
−5 
h, kJ/kg 
377 
367 
134 
— 
280 
284 
Calculate the heat transfer from the compressor, the heat transfer from the R410a in the condenser, and the heat transfer to the R410a in the evaporator.
FIGURE P4.123
ANSWER:
Solution 123 HP
Step 1 of 3
We have to calculate the heat transfer from the compressor, the heat transfer from the R410a in the condenser, and the heat transfer to the R410a in the evaporator.
The heat transfer from the compressor can be found from the energy equation.
Where,
0.05 kg/s
Enthalpy of R410a in state 1
= kJ/kg
Enthalpy of R410a in state 6
=kJ/kg
Thus,