An R-410a heat pump cycle shown in Fig. P4.123 has an

Chapter 4, Problem 123HP

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QUESTION:

Problem 123HP

An R-410a heat pump cycle shown in Fig. P4.123 has an R-410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:

State

1

2

3

4

5

6

P, kPa

3100

3050

3000

420

400

390

T, °C

120

110

45

 

−10

−5

h, kJ/kg

377

367

134

280

284

Calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

FIGURE P4.123

Questions & Answers

QUESTION:

Problem 123HP

An R-410a heat pump cycle shown in Fig. P4.123 has an R-410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:

State

1

2

3

4

5

6

P, kPa

3100

3050

3000

420

400

390

T, °C

120

110

45

 

−10

−5

h, kJ/kg

377

367

134

280

284

Calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

FIGURE P4.123

ANSWER:

Solution 123 HP

Step 1 of 3

We have to calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

The heat transfer from the compressor can be found from the energy equation.

Where,

0.05 kg/s

 Enthalpy of R-410a in state 1

      = kJ/kg

Enthalpy of R-410a in state 6

      =kJ/kg

Thus,

                         

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