# An R-410a heat pump cycle shown in Fig. P4.123 has an

Chapter 4, Problem 123HP

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QUESTION:

Problem 123HP

An R-410a heat pump cycle shown in Fig. P4.123 has an R-410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:

 State 1 2 3 4 5 6 P, kPa 3100 3050 3000 420 400 390 T, °C 120 110 45 −10 −5 h, kJ/kg 377 367 134 — 280 284

Calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

FIGURE P4.123

QUESTION:

Problem 123HP

An R-410a heat pump cycle shown in Fig. P4.123 has an R-410a flow rate of 0.05 kg/s with 5 kW into the compressor. The following data are given:

 State 1 2 3 4 5 6 P, kPa 3100 3050 3000 420 400 390 T, °C 120 110 45 −10 −5 h, kJ/kg 377 367 134 — 280 284

Calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

FIGURE P4.123

Solution 123 HP

Step 1 of 3

We have to calculate the heat transfer from the compressor, the heat transfer from the R-410a in the condenser, and the heat transfer to the R-410a in the evaporator.

The heat transfer from the compressor can be found from the energy equation.

Where,

0.05 kg/s

Enthalpy of R-410a in state 1

= kJ/kg

Enthalpy of R-410a in state 6

=kJ/kg

Thus,