PE Integrated Concepts Cold vaporizers pass a current through water, evaporating it with only a small increase in temperature. One such home device is rated at 3.50 A and utilizes 120 V AC with 95.0% efficiency. (a) What is the vaporization rate in grams per minute? (b) How much water must you put into the vaporizer for 8.00 h of overnight operation? (See Figure 20.42.)
Step-by-step solution Given : Current= 3.50 A Voltage =120 V AC Efficiency of the engine= 95.0% efficiency. Calculate : Vaporization rate in grams per minute.= How much water must you put into the vaporizer for 8.00 h = Step 1 of 4 The rate at which energy is produced through a current carrying element is given by equation (1) as below P= IV………………..(1) Here, I is the current and V is the voltage supplied. Step 2 of 4 The efficiency of vaporizer is 95%. So, heat generated will be, Q = (95/100) (IV) = (0.95) IV The heat energy generated will vaporize water. So,Specific heat of vaporization is given by mL v(0.95) IVt .......................(2) Here,L v the latent heat of vaporization of water.