An elastic cord vibrates with a frequency of 3.0 Hz when a mass of 0.60 kg is hung from it. What is its frequency if only 0.38 kg hangs from it?
Solution Step 1 Establishing what is calorific value. Calories are units of energy similar to joule. There are two categories for calories and they are small calorie (mainly used for thermochemical reactions) Large calorie or food calorie (For large energy calculations) Small calorie is represented using the unit “cal”. Large calorie is represented using the unit “Cal”. 1 large calorie = 1000 small calories Or, 1 Cal = 1000 cal. Here, we should use the large calorie for the energy calculation in food. Step 2 Converting small calorie to joules 1 small calorie is equivalent to 4.184 joules That is, 1 cal = 4.184 joules X small calorie = (X × 4.184) joules
Textbook: Physics: Principles with Applications
Author: Douglas C. Giancoli
The full step-by-step solution to problem: 5P from chapter: 11 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. This full solution covers the following key subjects: bacon, burger, Calories, cheese, contains. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The answer to “An elastic cord vibrates with a frequency of 3.0 Hz when a mass of 0.60 kg is hung from it. What is its frequency if only 0.38 kg hangs from it?” is broken down into a number of easy to follow steps, and 31 words. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. Since the solution to 5P from 11 chapter was answered, more than 835 students have viewed the full step-by-step answer.