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Calculate the forces FA and FB that the supports exert on

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 6P Chapter 9

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 6P

Calculate the forces FA and FB that the supports exert on the diving board of Fig. 9–42 when a 58-kg person stands at its tip. (a) Ignore the weight of the board. (b) Take into account the board’s mass of 35 kg. Assume the board’s CG is at its center.

FIGURE 9–42

Step-by-Step Solution:

Step 1 of 3 The impulse is large force acts on a body in short interval of time We know that p F t p F =k t where kis proportional constant its value is 1 F = mv because linear momentum p=mv t mv F = t here m is constant F t=mv F t=p where p=p -f i J = p -p f i J =mv- mu This theorem is called as impulse momentum theorem Step 2 of 3 Given u=5.5 m/s v=10.4 m/s J = p=p -p f i =mv- mu =m(10.4- 5.5)m/s = m 4.9m/s If F t=p Then F avg= p t m(4.9m/s) = t From second law F avg a= m m(4.9m/s) t = m t= 4.9 m/s a t= 4.9 m2s 9.8 m/s t=0.5 sec The stone will take 0.5 sec to increase its speed from 5.5 to 10.4 Step 2 of 3 Step 3 of 3

Step 3 of 3

Chapter 9, Problem 6P is Solved
Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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Calculate the forces FA and FB that the supports exert on

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