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3CQ A 0.2 kg plastic cart and a 20 kg lead cart can roll

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 3CQ Chapter 9

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 3CQ

3CQ A 0.2 kg plastic cart and a 20 kg lead cart can roll without friction on a horizontal surface. Equal forces are used to push both carts forward for a time of 1 s, starting from rest. After the force is removed at t = 1 s, is the momentum of the plastic cart greater than, less than, or equal to the momentum of the lead cart? Explain.

Step-by-Step Solution:

Step 1of 3 impulse is the measure of how much the force changes the momentum of an object. Impulse= force ×time= F × t p And we know that F = t So Impulse is J = p J =p f p i Step 2of 3 It is give that the 0.2 kg plastic cart and 20 kg lead cart roll from 1s from rest Impulse is given = F × t F and t are same So J 1J 2 J is the impulse for 0.2 kg plastic cart and 1 J is the impulse for 20...

Step 2 of 3

Chapter 9, Problem 3CQ is Solved
Step 3 of 3

Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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3CQ A 0.2 kg plastic cart and a 20 kg lead cart can roll

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