Two objects attract each other gravitationally with a force of 2.5 × 10−10 N when they are 0.25 m apart. Their total mass is 4.0 kg. Find their individual masses.
Solution 33P Consider the torque produced by the frictional force on your foot is net torque.but we ignore this frictional torque and others. We know that force acting on system F = 7.0 N r is distance from the chair’s rotation axis=0.40 m The angular acceleration is = 1.8 rad/m and angular acceleration is greater at the angle is 90 0 The total moment of inertia is given by the expression I = net I = rFsin()/ I = (0.40 m)(7.0 N)sin(90 )/(1.8 rad/s ) 2 I = 1.6 kg/m 2 Here we know from above result the mass distribution is so closer to axis of rotation ,so moment of inertia is small.