Let Fn be the determinant of the 1, 1, 1 tridiagonal matrix (n by n): Fn = det 1 1 1 1 1

Chapter 4, Problem 4.3.5

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Let Fn be the determinant of the 1, 1, 1 tridiagonal matrix (n by n): Fn = det 1 1 1 1 1 1 1 1 1 1 . By expanding in cofactors along row 1, show that Fn = Fn1 +Fn2. This yields the Fibonacci sequence 1,2,3,5,8,13,... for the determinants.

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