Solution Found!
If P1 is an even permutation matrix and P2 is odd, deduce from P1 +P2 = P1(P T 1 + P T 2
Chapter 4, Problem 4.9(choose chapter or problem)
If P1 is an even permutation matrix and P2 is odd, deduce from P1 +P2 = P1(P T 1 + P T 2 )P2 that det(P1 +P2) = 0.
Questions & Answers
QUESTION:
If P1 is an even permutation matrix and P2 is odd, deduce from P1 +P2 = P1(P T 1 + P T 2 )P2 that det(P1 +P2) = 0.
ANSWER:Step 1 of 4
A permutation matrix P has the same rows as the identity (in some order). There is a single “1” in every row and column. The most common permutation matrix is (As it exchanges nothing). The product of two permutation matrices is another permutation – the rows of I get reordered twice.
An even permutation matrix is when we can represent the matrix as a product of even number of transpositions. Determinant of even permutation matrix will be 1.
An odd permutation matrix is when we can represent the matrix as a product of odd number of transpositions. Determinant of an odd permutation matrix will be -1.